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EDO
LINEALES de ORDEN 1 |
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Ejercicios 2 |
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| 1) |
y ' + 2xy = 4x |
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Sol: |
y = 2 + c·e |
- x2 |
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| 2) |
xy ' = y + x3 + 3x2 - 2x |
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Sol: |
y
= 1/2 x3 + 3 x2 - 2 x L x + c x |
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| 3) |
(x-2) y ' = y + 2(x-2)3 |
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Sol: |
y = (x-2)3 + c (x-2) |
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| 4) |
x3y ' + (2 - 3x2)y = x3 |
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Sol: |
y = 1/2 x3 + c x3 e |
1/x2 |
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| 5) |
y ' + y = 2 + 2x |
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Sol: |
y = 2x + c·e-x |
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| 6) |
xy '- 2y = (x - 2) ex |
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Sol: |
y = ex + c·x2 |
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| 7) |
y ' + y cos x = sen x cos x |
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Sol: |
y = sen
x -1 + c·e-sen x |
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Solución : |
f(x) = cos x ; g(x) = sen x cos x |
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dy |
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∫ |
dy |
=∫ |
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a) Homogenea: |
y ' + y cos x = 0 |
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= |
- y cos x |
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-cos x dx |
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ya = e |
-sen x |
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dx |
y |
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∫ |
g |
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∫ |
sen
x cos x |
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∫ |
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sen x = t |
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b) |
G(x) = |
dx |
= |
dx |
= |
sen x cos x e |
sen x |
dx |
= |
C.V. |
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ya |
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e |
-sen x |
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cos x dx = dt |
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∫ |
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u = t |
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-∫ |
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= |
t et dt |
= |
P.P. |
= t et |
et dt = t et - et + c |
= sen
x esen x- esen x + c |
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dv = et dt |
; v = et |
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c) Solución: |
y(x) = ya(x) · G(x) |
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y = e-sen
x (sen x esen x- esen x + c) |
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y = sen x
-1 + c·e-sen x |
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| 8) |
xy ' = y (1 - x tg x) + x2 cos x |
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Sol: |
y = x2 cos x + c x cos x |
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