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FRACCIONADO FRANCÉS |
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CASO particular para FRACCIONAMIENTO de
INTERESES |
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| - |
Al fraccionar exigimos que los términos
amortizativos al final de cada año, a, sean iguales. |
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a = Is+As |
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Is = Cs-1 · i(k) |
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I1 |
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I1 |
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I1 |
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I1 |
a |
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C0 |
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A1 |
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I2 |
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I2 |
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I2 |
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I2 |
a |
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C1 |
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I3 |
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I3 |
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I3 |
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I3 |
a |
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C2 |
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A3 |
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C3 |
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i(k) |
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··· |
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··· |
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··· |
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··· |
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t0 |
(1,1) |
(1,2) |
(1,k-1) |
t1 |
(2,1) |
(2,2) |
(2,k-1) |
t2 |
(3,1) |
(3,2) |
(3,k-1) |
t3 |
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| - |
Luego visto anualmente obtenemos un
préstamo francés con el tipo i(k). |
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C0 |
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I1+A1 = a |
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I2+A2 = a |
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I3+A3 = a |
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··· |
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i(k) |
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t0 |
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t1 |
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t2 |
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t3 |
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Con, |
C0 = a·an| i(k) |
=> |
a = C0/an| i(k) |
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| - |
Cuadro de amortización con, As' = 0 si h ≠ k , y , As' = As si h = k |
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( s,h ) |
s' |
is' |
as' |
Is' |
As' |
Ms' |
Cs' |
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i(k) |
As' + Is' |
Cs'-1 · i(k) |
0 ; As |
C0 - Cs' |
Cs'-1 - As' |
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··· |
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( r-1,k ) |
r'-2 |
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Cs-1 |
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( r,1 ) |
r'-1 |
i(k) |
Is |
Is |
0 |
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Cs-1 |
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( r,h ) |
r' |
i(k) |
Is |
Is |
0 |
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Cs-1 |
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( r,k ) |
r'+1 |
i(k) |
a |
Is |
a - Is |
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Cs |
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( r+1,1 ) |
r'+2 |
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| 3 |
EJEMPLO |
Sea un préstamo de 10.000 € que se
amortizará en tres años de la |
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siguiente forma : Cada mes se abonarán
únicamente los intereses correspondientes, |
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al tanto nominal del 6%, salvo el último
de cada año que además de los intereses se |
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amortizará capital y además todos los
pagos del último mes de cada año son iguales. |
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Se pide construir el cuadro de
amortización. |
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